5x^2-10x-4=2x+4

Solution for 5x^2-10x-4=2x+4 equation:

5x^2-10x-4=2x+4

We move all terms to the left:

5x^2-10x-4-(2x+4)=0

We get rid of parentheses

5x^2-10x-2x-4-4=0

We add all the numbers together, and all the variables

5x^2-12x-8=0

a = 5; b = -12; c = -8;
Δ = b2-4ac
Δ = -122-4·5·(-8)
Δ = 304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{304}=\sqrt{16*19}=\sqrt{16}*\sqrt{19}=4\sqrt{19}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{19}}{2*5}=\frac{12-4\sqrt{19}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{19}}{2*5}=\frac{12+4\sqrt{19}}{10}
$